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• Two taps fill a tank in 6 hours. Alone, one of them spends 5 hours more than the other. Determine the time it takes one of them to fill this tank in isolation.
Solution:
Consider x the time taken for the 1st tap to fill the tank and x + 5 the time taken for the 2nd tap to fill the tank.
Within an hour, each tap fills the following fraction of the tank: In an hour, the two taps together will fill of the tank; look at the corresponding equation: Solving it, we have:
6 (x + 5) + 6x = x (x + 5)
6x + 30 + 6x = x2 + 5x
x2 - 7x - 30 = 0
x '= - 3 and x "= 10
Since the negative root is not used, we will have x = 10 as a solution.
Answer: The first tap fills the tank in 10 hours and the second tap in 15 hours.
• At a celebration dinner, a prize of R $24,000.00 would be distributed equally among the guests. As 5 people were missing, each of the gifts received an increase of$ 400.00 in your prize. How many people were present at this dinner?
Solution:
We can represent by: Solving it: Answer: At this dinner 20 people should be present. As there were 5, so 15 people were present at dinner.
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