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We start with the following equality, which we assume to be true:
a + b = c
We can write equality as follows:
(8a-7a) + (8b-7b) = (8c-7c)
Putting all multiples of 7 on one side and 8 on the other, we have:
8a + 8b-8c = 7a + 7b-7c
Highlighting 7 on one side and 8 on the other, we have:
8 (a + b-c) = 7 (a + b-c)
Dividing both sides by a + b-c we have:
8 = 7
Obviously this demonstration has an error because we all know that 8 is not equal to 7 (or does anyone have any questions?). Click below to find out what the error is:
In this demonstration comes a stage where we have:
8 (a + b-c) = 7 (a + b-c)
According to the demonstration, the next step is to divide both sides by a + b-c.
There is the mistake !!!
It is wrong because at first we assume that a + b = c, so a + b-c is worth zero. Division by zero does not exist !!!
Next: Negative Sum
